2
void myPrintf(const char* format, ...) {
    // some code
    va_list vl;
    printf(format, vl);
}

int main() {
    myPrintf("%d\n", 78);
}

In this code I have tried to pass the argument from ellipsis to printf. It compiles but prints garbage instead of 78. What is the right way of doing it?

Jonathan Leffler
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Ashot
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3 Answers3

7

You need to do the following:

void myPrintf(const char *format, ...) {
    va_list vl;
    va_start(vl, format);
    vprintf(format, vl);
    va_end(vl);
}

Please note the use of vprintf instead of printf.

Abrixas2
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1

Two problems:

  1. The first is that you don't initialize vl, use va_start for that. Don't forget to use va_end afterwards.

  2. The other problem is that printf doesn't take a va_list argument. Use vprintf for that.

Some programmer dude
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0

First Initialize vl

va_start(vl,1); //No. of arguments =1

Then take the int from it

printf(format, va_arg(vl,int));

P0W
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