Java Regular expression exclude special characters

Question

I have to validate a String to check if it contains a special character or not. This string may contain any number and words ( including unicode, ie: à, â,ô .. ) but should not accept any special characters ( ie: !,@,#,%,^ ... )

Sorry for my bad English.

English is just fine, but your effort is not. What did you try? — Pete B., Aug 22 '13 at 08:30

Marko Topolnik · Accepted Answer · 2013-08-22T08:40:56.700

2

This character class

[\p{L}\p{No}\p{Space}]

will include all characters which Unicode declares as either "letters", "numbers", or "whitespace characters". If you want to match a string against such a character class, you would write the following:

input.matches("[\\p{L}\\p{No}\\p{Space}]+")

For future reference, I have extracted all this information from the java.util.Pattern class. You should refer to that page for all your future interest in the Java regular expressions.

edited Aug 22 '13 at 08:40

answered Aug 22 '13 at 08:30

Marko Topolnik

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[\p{L}\p{No}\p{Space}] It's works. Thank you – user2090487 Aug 22 '13 at 09:14

score 0 · Answer 2 · answered Aug 22 '13 at 08:33

0

You can try [\\p{L}\\s]+. as example. This will remove special characters.

   Pattern p=Pattern.compile("[\\p{L}\\s]+");
    Matcher m=p.matcher("hissd@");
    if(m.find()){
        System.out.println(m.group(0));//
    }

answered Aug 22 '13 at 08:33

Ruchira Gayan Ranaweera

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Java Regular expression exclude special characters

2 Answers2