Convert datetime format into seconds

Question

My date is in the format DD/MM/YYYY HH:MM:SS , ie 16/08/2013 09:51:43 . How can I convert the date into python seconds using total_seconds() or using any other python function?

What are "python seconds" do you mean a unix timestamp? – Wolph Aug 16 '13 at 09:18 — Wolph, Aug 16 '13 at 09:18

score 21 · Accepted Answer · edited May 23 '17 at 11:45

21

Here's how you can do it:

>>> from datetime import datetime
>>> import time
>>> s = "16/08/2013 09:51:43"
>>> d = datetime.strptime(s, "%d/%m/%Y %H:%M:%S")
>>> time.mktime(d.timetuple())
1376632303.0

Also see Python Create unix timestamp five minutes in the future.

edited May 23 '17 at 11:45

Community

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answered Aug 16 '13 at 09:20

alecxe

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score 11 · Answer 2 · answered Aug 16 '13 at 09:36

11

>>> tt = datetime.datetime( 2013, 8, 15, 6, 0, 0 )
>>> print int(tt.strftime('%s'))
1376535600

answered Aug 16 '13 at 09:36

Adem Öztaş

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Jiri · Answer 3 · 2013-08-16T12:16:16.467

9

Seconds since when?

See this code for general second computation:

from datetime import datetime
since = datetime( 1970, 8, 15, 6, 0, 0 )
mytime = datetime( 2013, 6, 11, 6, 0, 0 )
diff_seconds = (mytime-since).total_seconds()

UPDATE: if you need unix timestamp (i.e. seconds since 1970-01-01) you can use the language default value for timestamp of 0 (thanks to comment by J.F. Sebastian):

from datetime import datetime
mytime = datetime( 2013, 6, 11, 6, 0, 0 )
diff_seconds = (mytime-datetime.fromtimestamp(0)).total_seconds()

edited Aug 16 '13 at 12:16

answered Aug 16 '13 at 09:47

Jiri

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if `mytime` is a local time then you could use `datetime.fromtimestamp(0)` to get `since` value. – jfs Aug 16 '13 at 11:24

Convert datetime format into seconds

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