get user name from an E-mail address in php

Question

In PHP, I have a string like this:

$string = "user@domain.com";

How do I get the "user" from email address only? Is there any easy way to get the value before @?

Answer 1

Assuming the email address is valid, this textual approach should work:

$prefix = substr($email, 0, strrpos($email, '@'));

It takes everything up to (but not including) the last occurrence of @. It uses the last occurrence because this email address is valid:

"foo\@bar"@iana.org

If you haven't validated the string yet, I would advice using a filter function:

if (($email = filter_var($email, FILTER_VALIDATE_EMAIL)) !== false) {
    // okay, should be valid now
}

Answer 2

Try the following:

$string = "user@domain.com";

$explode = explode("@",$string);

array_pop($explode);

$newstring = join('@', $explode);

echo $newstring;

Modified for multiple '@' symbols.

Answer 3

There’s a nice example in the PHP manual entry for the strpos() function: http://php.net/manual/en/function.strstr.php#117530

PHP makes this easy for you. When working with domain portion of email addresses, simply pass the return of strstr() to substr() and start at 1:

substr(strstr($haystack, '@'), 1);

Answer 4

You can use

$user = implode('@', explode('@', $email, -1));

or

$user = substr($email, 0, strrpos($mail, '@'));

Answer 5

In the simplest form (assuming single '@'), you can follow @Ben Fortune's answer (using explode()).

Otherwise, try this:

$email1 = "foo@example.com";
$email2 = "b\@r@example.com";

preg_match_all ("/^(.+)@[^@]+$/", $email1, $e1);
preg_match_all ("/^(.+)@[^@]+$/", $email2, $e2);

echo "Emails: {$e1[1][0]} and {$e2[1][0]}\n";
// Result: Emails: foo and b\@r