How to trim a list with duplicated elements in Python?

Question

I wish to trim the list

[0,0,0,0,0,0,1,1,1,1,2,2,2,2,2,2,2,3,3,3,3, ... , 145,145,145]

into

[0,1,2,3,4,...,145]

I know the "C-Programming-style" way of doing it in Python.

I am here to ask for an intelligent and smart way of doing this.

@Josh Inspect carefully and then speak. If I use the solution given there, I would end up with an empty list. — Sibbs Gambling, Aug 02 '13 at 02:37
@perfectionm1ng That question asked what you are asking with one more step afterwards. All you needed was the first step. If you need another duplicate question closer to yours: http://stackoverflow.com/questions/479897/how-do-you-remove-duplicates-from-a-list-in-python-if-the-item-order-is-not-impo — scohe001, Aug 02 '13 at 02:40
If the items are in order as in your example, use itertools.groupby — John La Rooy, Aug 02 '13 at 02:46
The question is unclear... unfortunately. Is this like set op, set + sort, or Unix style uniq? — Antti Haapala -- Слава Україні, Aug 02 '13 at 02:47

score 1 · Accepted Answer · answered Aug 02 '13 at 02:37

1

numpy.unique(mylist) or list(set(mylist)) should do.

PS And it is not 'trimming' - that's a different thing...

answered Aug 02 '13 at 02:37

sashkello

score 1 · Answer 2 · answered Aug 02 '13 at 02:39

1

unique = [x for x in set(original)]

or

unique = list(set(original))

answered Aug 02 '13 at 02:39

jason

score 0 · Answer 3 · answered Aug 02 '13 at 02:37

0

Give this a try

print list(set(my_list))

answered Aug 02 '13 at 02:37

scohe001

3 Answers3