double foo = 3;
double bar = 2.1;
System.out.println(foo - bar + "");
Output:
0.8999999999999999
Why? Is this some Java joke, which is not understandable for mere mortals?
Asked
Active
Viewed 68 times
-1
Lajos Arpad
- 53,986
- 28
- 88
- 159
1 Answers
4
It isn't a joke. It is floating-point precision error problem. The main gist of this problem is that floating points are represented in base 2 rather than 10, and that the precision of doubles is not arbitrary.
If you want precision, you can use BigDecimal class:
jh314
- 25,902
- 15
- 60
- 80
-
Thank you, this pretty much sums up things. – Lajos Arpad Jul 20 '13 at 02:48