can two IF condition work simultaneously

Question

I created a js program to check a condition using two IF conditions simultaneously. Why doesnt it work? fiddle

    function displayIcon() {
    var a = 1;
    var i = 2;
    if (a == 1) {

        $('.clist').show();
        $('.vPrint').show();
        $('.vFilter').show();
        $('.vSaveAs').show();
        $('.vShare').show();
    } else if (a === 0) {

        $('.vPrint').show();
        $('.vFilter').show();
    }

    if (i == 2) {
        $('.alertInfo').show();
    } else if (i == 4) {
        $('.alertInfo').hide();
    }
}

You should be adding a jquery library to the fiddle.. Also change the "===" to "==" This should work.. — Roy M J, Jul 18 '13 at 11:44
http://stackoverflow.com/questions/523643/difference-between-and-in-javascript bit of further reading... — zik, Jul 18 '13 at 15:07

score 3 · Answer 1 · answered Jul 18 '13 at 11:38

It works just fine for me. All you have to do to make it work in jsFiddle is:

Enable the jQuery plugin, so that $ is defined; and
Change the function wrapping to "no wrap", otherwise the displayIcon function is only defined within the wrapper and cannot be accessed by the button.

score 1 · Answer 2 · answered Jul 18 '13 at 11:42

1

Your fiddle had 2 issues:

You're calling jQuery functions without loading jQuery
Your displayIcon function wasn't defined in the same scope that you were trying to call it from

Here's an updated version that should work.

answered Jul 18 '13 at 11:42

André Dion

20,347
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score 1 · Answer 3 · answered Jul 18 '13 at 11:43

You need to enable jQuery.

You could also consider using a switch:

switch(a) {
    case 1: 
        $('.clist').show();
        $('.vPrint').show();
        $('.vFilter').show();
        $('.vSaveAs').show();
        $('.vShare').show();
        break;
    case 0:
        $('.vPrint').show();
        $('.vFilter').show();
        break;
}

score 0 · Answer 4 · answered Jul 18 '13 at 11:44

0

Here is the working fiddle for you

var s = document.getElementById("myctrl");
s.onclick = function displayIcon() {

answered Jul 18 '13 at 11:44

Vinod Louis

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score 0 · Answer 5 · answered Jul 18 '13 at 11:45

0

In fiddle change 'onLoad' option into No wrap in body. Then add jquery plugin.

answered Jul 18 '13 at 11:45

sachin

12,165
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score 0 · Answer 6 · answered Sep 02 '13 at 09:29

0

Thanks everyone, I've got the answer to the question I asked. Two IF conditions can work together. The following code provides the needful.

int a=2, b=3;
if(a<b)
{
alert("B is bigger");
}
if(b<a)
{
alert("A is bigger");
}

answered Sep 02 '13 at 09:29

Fight code with code

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can two IF condition work simultaneously

6 Answers6