How can I check if a variable contains another variable within a windows batch file?

Question

Assuming the following batch file

set variable1=this is variable1
set variable2=is
set variable3=test

if variable1 contains variable2 (
    echo YES
) else (
    echo NO
)

if variable1 contains variable3 (
    echo YES
) else (
    echo NO
)

I want the output to be a YES followed by a NO

Answer 1

I've resolved this with the following

setLocal EnableDelayedExpansion

set variable1=this is variable1
set variable2=is
set variable3=test

if not "x!variable1:%variable2%=!"=="x%variable1%" (
    echo YES
) else (
    echo NO
)

if not "x!variable1:%variable3%=!"=="x%variable1%" (
    echo YES
) else (
    echo NO
)

endlocal

I got the basic idea from the following answer but it wasn't searching by a variable so it wasn't completely what I was looking for.

Batch file: Find if substring is in string (not in a file)

Answer 2

another way:

echo/%variable1%|find "%variable2%" >nul
if %errorlevel% == 0 (echo yes) else (echo no)

the / prevents output of Echo is ON or Echo is OFF in case %variable1% is empty.

Answer 3

Gary Brunton's answer did not work for me.

If you try with set variable1="C:\Users\My Name\", you will end up with an error :

 'Name\""' is not recognized as an internal or external command

Adapting this answer Find out whether an environment variable contains a substring, I ended up with :

echo.%variable1%|findstr /C:"%variable2%" >nul 2>&1
if not errorlevel 1 (
   echo Found
) else (
   echo Not found
)