Ampersand after function declaration

Asked Jul 11 '13 at 17:33

Active Jul 11 '13 at 17:42

Viewed 211 times

I came across this piece of code recently

T operator () () &
{
...
}

T operator () () &&
{
...
}

and I'm confused. What do the & and && mean in this context? Is this similar to a copy & move constructor but for functions?

edited Jul 11 '13 at 17:42

chris

asked Jul 11 '13 at 17:33

user1233963

7

Voting to close, but +1, because this question has good search terms. – ruakh Jul 11 '13 at 17:37
Another good link: [RValue references and Move Semantics](http://www.cprogramming.com/c++11/rvalue-references-and-move-semantics-in-c++11.html) – paulsm4 Jul 11 '13 at 17:38
I changed your tag. It's a C++11 feature. – chris Jul 11 '13 at 17:42

0 Answers0