74

I've written a command line utility that uses getopt for parsing arguments given on the command line. I would also like to have a filename be an optional argument, such as it is in other utilities like grep, cut etc. So, I would like it to have the following usage

tool -d character -f integer [filename]

How can I implement the following?

  • if a filename is given, read from the file.
  • if a filename is not given, read from STDIN.
Ryan R. Rosario
  • 4,904
  • 9
  • 38
  • 56
  • 2
    see also http://unix.stackexchange.com/questions/47098/how-do-i-make-python-programs-behave-like-proper-unix-tools/47543#47543 – magnetar Sep 08 '12 at 12:18

8 Answers8

89

The fileinput module may do what you want - assuming the non-option arguments are in args then:

import fileinput
for line in fileinput.input(args):
    print line

If args is empty then fileinput.input() will read from stdin; otherwise it reads from each file in turn, in a similar manner to Perl's while(<>).

SimonJ
  • 20,646
  • 1
  • 34
  • 49
  • This was just as good of an answer, but isn't quite as generalizable. I will remember to use fileinput next time if appropriate. – Ryan R. Rosario Nov 30 '09 at 22:47
  • Right, but if you're using `getargs` (as the OP is) then you probably just want to pass the leftover args rather than `sys.argv[1:]` (which is the default). – SimonJ Mar 07 '15 at 22:51
  • 2
    fileinput is a strange and annoying API, it forces you to use flagged arguments on the command line. – ctpenrose May 08 '15 at 19:13
  • 2
    @ctpenrose It is not a fileinput design fault: distinguishing arguments that are the names of input files from other arguments is an issue that is inherent to the problem domain. Fileinput (especially with argparse) simplifies the use of a common pattern for doing this, which you can choose to use or not, but if have some other way of making the distinction, you can send a slice of sys.argv (or a different array of names altogether) to fileinput.input() - and you do not have to put in a fake sys.argv[0] when you explicitly pass an array. – sdenham Jan 26 '18 at 16:34
69

In the simplest terms:

import sys
# parse command line
if file_name_given:
    inf = open(file_name_given)
else:
    inf = sys.stdin

At this point you would use inf to read from the file. Depending on whether a filename was given, this would read from the given file or from stdin.

When you need to close the file, you can do this:

if inf is not sys.stdin:
    inf.close()

However, in most cases it will be harmless to close sys.stdin if you're done with it.

Greg Hewgill
  • 890,778
  • 177
  • 1,125
  • 1,260
  • @thefourtheye: Yes, both those functions will read from either a file or from `sys.stdin`. – Greg Hewgill May 03 '13 at 18:41
  • 3
    I found another way to solve this problem, I blogged about it here http://dfourtheye.blogspot.in/2013/05/python-equivalent-of-cs-freopen.html and added an answer to this question as well. – thefourtheye May 04 '13 at 02:16
  • 1
    @thefourtheye have deleted their answer; you probably don't need to click through to a blog to discover `sys.stdin = open(file_name)` – tripleee Jan 13 '21 at 05:34
20

I like the general idiom of using a context manager, but the (too) trivial solution ends up closing sys.stdin when you are out of the with statement, which I want to avoid.

Borrowing from this answer, here is a workaround:

import sys
import contextlib

@contextlib.contextmanager
def _smart_open(filename, mode='Ur'):
    if filename == '-':
        if mode is None or mode == '' or 'r' in mode:
            fh = sys.stdin
        else:
            fh = sys.stdout
    else:
        fh = open(filename, mode)
    try:
        yield fh
    finally:
        if filename != '-':
            fh.close()
    
if __name__ == '__main__':
    args = sys.argv[1:]
    if args == []:
        args = ['-']
    for filearg in args:
        with _smart_open(filearg) as handle:
            do_stuff(handle)

I suppose you could achieve something similar with os.dup() but the code I cooked up to do that turned out to be more complex and more magical, whereas the above is somewhat clunky but very straightforward.

bryant1410
  • 4,712
  • 3
  • 36
  • 37
tripleee
  • 158,107
  • 27
  • 234
  • 292
  • Thanks a lot! This is what exactly I was looking for. Very clear and straight forward solution. – edison Nov 15 '17 at 13:43
  • This is also a useful bit of code to use when `argparse.FileType` just gets too annoying (which happens fairly often for me). – travc Apr 19 '19 at 19:45
16

I prefer to use "-" as an indicator that you should read from stdin, it's more explicit:

import sys
with open(sys.argv[1], 'r') if sys.argv[1] is not "-" else sys.stdin as f:
    pass # do something here
Phil L.
  • 2,481
  • 1
  • 15
  • 11
14

To make use of python's with statement, one can use the following code:

import sys
with open(sys.argv[1], 'r') if len(sys.argv) > 1 else sys.stdin as f:
    # read data using f
    # ......
Roun
  • 1,369
  • 1
  • 17
  • 25
11

Not a direct answer but related.

Normally when you write a python script you could use the argparse package. If this is the case you can use:

parser = argparse.ArgumentParser()
parser.add_argument('infile', nargs='?', type=argparse.FileType('r'), default=sys.stdin)

'?'. One argument will be consumed from the command line if possible, and produced as a single item. If no command-line argument is present, the value from default will be produced.

and here we set default to sys.stdin;

so If there is a file it will read it , and if not it will take the input from stdin "Note: that we are using positional argument in the example above"

for more visit: https://docs.python.org/2/library/argparse.html#nargs

Medhat
  • 1,494
  • 15
  • 30
5

Switch to argparse (it's also part of the standard library) and use an argparse.FileType with a default value of stdin:

import  argparse, sys

p = argparse.ArgumentParser()
p.add_argument('input', nargs='?',
  type=argparse.FileType(), default=sys.stdin)
args = p.parse_args()

print(args.input.readlines())

This will not let you specify encoding and other parameters for stdin, however; if you want to do that you need to make the argument non-optional and let FileType do its thing with stdin when - is given as an argument:

p.add_argument('input', type=FileType(encoding='UTF-8'))

Take heed that this latter case will not honour binary mode ('b') I/O. If you need only that, you can use the default argument technique above, but extract the binary I/O object, e.g., default=sys.stdout.buffer for stdout. However, this will still break if the user specifies - anyway. (With - stdin/stdout is always wrapped in a TextIOWrapper.)

If you want it to work with -, or have any other arguments you need to provide when opening the file, you can fix the argument if it got wrapped wrong:

p.add_argument('output', type=argparse.FileType('wb'))
args = p.parse_args()
if hasattr(args.output, 'buffer'):
    #   If the argument was '-', FileType('wb') ignores the 'b' when
    #   wrapping stdout. Fix that by grabbing the underlying binary writer.
    args.output = args.output.buffer

(Hat tip to medhat for mentioning add_argument()'s type parameter.)

cjs
  • 23,786
  • 6
  • 86
  • 97
1

Something like:

if input_from_file:
    f = open(file_name, "rt")
else:
    f = sys.stdin
inL = f.readline()
while inL:
    print inL.rstrip()
    inL = f.readline()
GreenMatt
  • 17,688
  • 7
  • 50
  • 76