Calling itertools.product with unkown number of args

Question

I hope this is a easy one.

Is there any possiblity to call itertools.product with a yet (not hardcoded) not knwon number of arguments?

Something like this:

itertools.product(x[0],x[1],x[2],....)

and the dimension of x can't be hardcoded

Thanks!

why not `itertools.product(x)`? – michaelmeyer Jun 21 '13 at 13:30 — michaelmeyer, Jun 21 '13 at 13:30

score 3 · Accepted Answer · answered Jun 21 '13 at 13:30

3

Try:

itertools.product(*x)

answered Jun 21 '13 at 13:30

arshajii

score 2 · Answer 2 · answered Jun 21 '13 at 13:30

2

You can use

itertools.product(*x)

answered Jun 21 '13 at 13:30

Phae7rae

score 1 · Answer 3 · edited May 23 '17 at 10:32

1

a = [1,2,3]
b = [2,3,4]
c= [a,b]

itertools.product(*c)

You can pass array of arguments using *

edited May 23 '17 at 10:32

Community

answered Jun 21 '13 at 13:34

3 Answers3