Pythonic way of doing this?

Question

I have this code construct:

flag = True
while flag:
    do_something()
    if some_condition:
        flag = False

Is it the best way to do that? Or is there a better pythonic way?

related: http://stackoverflow.com/questions/743164/do-while-loop-in-python — georg, Jun 20 '13 at 13:40

unutbu · Accepted Answer · 2013-06-20T13:46:03.163

4

while True:
    do_something()
    if some_condition: break

or

while not some_condition:
    do_something()

For the second option to be equivalent to the first, some_condition must start as False so do_something() will get called at least once.

edited Jun 20 '13 at 13:46

answered Jun 20 '13 at 13:36

unutbu

score 1 · Answer 2 · answered Jun 20 '13 at 13:57

def late(cond):
    yield None
    while cond(): yield None

for _ in late(lambda: condition):
    do_something()

Looks weird. What happens here?

The late() generator forst yields a value in order to enter the loop unconditionally. And in every successive loop run, the cond() is checked.

2 Answers2