I plan to insert string (colon) in between HEX in Python, i.e;
before: AABBCCDDEEFF112233 after: AA:BB:CC:DD:EE:FF:11:22:33
Can anybody here shed some light on how to achieve it.
Regards,
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2Have you tried solving your problem yourself before asking others to do it for you? – Blender Jun 17 '13 at 00:09
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1Use the grouper itertools recipe: http://docs.python.org/2/library/itertools.html#recipes and then join on `":"`. Done. – Patashu Jun 17 '13 at 00:10
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1Break it up into 2 character strings and then `':'.join(pieces)`. – martineau Jun 17 '13 at 00:11
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`s = "AABBCCDDEEFF112233"\n"".join([(c if idx % 2 == 0 else c + ":") for c, idx in zip(s, range(0, len(s)))]).rstrip(":")` – Charles Salvia Jun 17 '13 at 00:18
1 Answers
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The answer to your question is here: Pythonic way to insert every 2 elements in a string
You could also use a step i.e. str[::x] to loop over every 2 characters to achieve this result.
myStr = 'AABBCCDDEEFF112233'
print ':'.join(myStr[i:i+2] for i in range(0, len(myStr), 2))
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Mr. Polywhirl
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You shouldn't name variables something that collides with a built-in. – martineau Jun 17 '13 at 00:57
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