What does this regex `str.gsub(/\#{(.*?)}/)` do?

Question

.* means any character, so why is the .*? needed in the following?

str.gsub(/\#{(.*?)}/) {eval($1)}

the ? means: make the quantifier lazy. take a look at this site:www.regular-expressions.info — Casimir et Hippolyte, Jun 12 '13 at 04:56
This regex will do something, which you should only do with `$SAFE >= 1` on. — Boris Stitnicky, Jun 12 '13 at 05:00

score 7 · Accepted Answer · edited Jun 12 '13 at 05:19

.* is a greedy match, whereas .*? is a non-greedy match. See this link for a quick tutorial on them. Greedy matches will match as much as they can, while non-greedy matches will match as little as they can.

In this example, the greedy variant grabs everything between the first { and the last } (the last closing brace):

'start #{this is a match}{and so is this} end'.match(/\#{(.*)}/)[1]
# => "this is a match}{and so is this"

while the non-greedy variant reads as little as it needs to make the match, so it only reads between the first { and the first successive }.

'start #{this is a match}{and so is this} end'.match(/\#{(.*?)}/)[1]
# => "this is a match"

What does this regex `str.gsub(/\#{(.*?)}/)` do?

1 Answers1