Basic String Array in c

Asked May 29 '13 at 14:05

Active May 29 '13 at 14:06

Viewed 69 times

char p[10]="Hello world";
printf("%u %u",&p,p);

Output:

4294959568 4294959568

Why both are giving the same value? &p should give the address of where it is storing the array address right?

What happens when an array is defined? What value will be there in p and the array is accessed?

edited May 29 '13 at 14:06

awesoon

asked May 29 '13 at 14:05

user1762571

Look at [this](http://stackoverflow.com/questions/9552663/function-pointers-and-address-of-a-function). – awesoon May 29 '13 at 14:10
Not an answer but you can use `%p` for pointers `printf("%p %p",&p,p);` – Shafik Yaghmour May 29 '13 at 14:10
As char array represents the string so 'p' is the pointer to the string while '&p[0]' is the addres of the first char of the array. – suneet saini May 29 '13 at 14:14
euhhh, any link to the duplicate? – Joe DF May 29 '13 at 17:26

0 Answers0