about sizeof(char *) and sizeof(char[])

Question

char *str1 = "pupupupu";
char str2[] = "pupupupu";

printf("%s\t%d\n", str1, (int)sizeof(str1));
printf("%s\t%d\n", str2, (int)sizeof(str2));

Output:

pupupupu    8
pupupupu    9

My question: Why are the two output sizes different?

score 2 · Accepted Answer · edited May 23 '17 at 11:57

2

sizeof(str1) is size of char pointer where as sizeof(str2) gives size of array that is string length (pupupupu) + 1

Read my this answer, its not exactly same but help you much: What does sizeof(&arr) returns?

edited May 23 '17 at 11:57

Community

answered May 17 '13 at 12:58

Grijesh Chauhan

because my computer is X64,so size of a pointer is 8bit,it makes me confused before(my example string has 8 chars),thank you for your answer! – pupu007 May 17 '13 at 13:50
@pupu007 Yes PuPu..you correctly got the point – Grijesh Chauhan May 18 '13 at 04:24

1 Answers1