I have a decimal number in the bash shell:
linux$ A=67
How do I print 67 as hexadecimal in bash?
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2the printf in bash is a builtin, it does not fork a shell. I have changed my answer to give an example of it directly setting variables as in the question – Vorsprung May 13 '13 at 17:46
1 Answers
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As a bash program:
#!/bin/bash
decimal1=31
printf -v result1 "%x" "$decimal1"
decimal2=33
printf -v result2 "%x" "$decimal2"
echo $result1 $decimal1
echo $result2 $decimal2
Or directly from the bash shell:
el@defiant ~ $ printf '%x\n' 26
1a
el@defiant ~ $ echo $((0xAA))
170
el@defiant ~ $
Eric Leschinski
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Vorsprung
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2+1 and acceptance for the information: `the printf in bash is a builtin, it does not fork a shell.` – MOHAMED May 13 '13 at 17:50
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`printf` is also part of `coreutils` - `printf '%x\n' $1` in a shell script does the job: `/path/to/script 26` – Stuart Cardall Mar 09 '17 at 22:03