jQuery has/ contains words

Question

I'd like to achieve that, if "clientpsseabq" string is contained in variable Var_words then equal true, else false. I just have no idea what method or function do I need to use?

var Var_words = "https://www.go.me/outputsearchs/clientpsseabq"

if ( Var_words contains string "`clientpsseabq`"){
   return true;
}else{
   return false;
}

if someone could help me how can I complete this task?

score 3 · Answer 1 · answered Apr 22 '13 at 09:04

3

You can try this

if (Var_words.indexOf("clientpsseabq") >= 0)

or with care of case sensitivity

if (Var_words.toLowerCase().indexOf("clientpsseabq") >= 0)
{
   // your code
}

answered Apr 22 '13 at 09:04

Sachin

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Bojangles · Accepted Answer · 2013-04-22T21:12:26.663

3

Use the (native JavaScript) function String.indexOf():

if(Var_words.indexOf('clientpsseabq') !== -1) {
    return true;
} else {
    return false;
}

.indexOf() returns the index of the string. If the string is not found, it returns -1.

A smaller, cleaner solution would be to simply return the value of the conditional directly:

return (Var_words.indexOf('clientpsseabq') !== -1);

edited Apr 22 '13 at 21:12

answered Apr 22 '13 at 09:05

Bojangles

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thanks for the answer, `indexof` should be `indexOf` otherwise, it doesnt work. – olo Apr 22 '13 at 20:33
1

So it should, thanks. I must've mistyped it in my haste – Bojangles Apr 22 '13 at 21:12

score 1 · Answer 3 · edited Apr 22 '13 at 09:24

1

 if(Var_words.indexOf("clientpsseabq") >= 0))
 {

 }

edited Apr 22 '13 at 09:24

andy

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answered Apr 22 '13 at 09:06

Mahesh Patidar

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15

score 1 · Answer 4 · answered Apr 22 '13 at 09:06

1

use a regular expression to test for the case

if(/clientpsseabq/.test(Var_words)){
    //given string exists
} else {
    //given string does not exists
}

answered Apr 22 '13 at 09:06

Arun P Johny

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jQuery has/ contains words

4 Answers4