javascript variable alone on a line, why?

Question

var popup = window.open('http://twitter.com');
popup;
if ($.browser.safari && !popup) {
alert('Please allow for popups on your browser.');
}

I came across the above code today, what (if any) is the reason for the second line "popup;" ?

Tried it on chrome it doesnt do anything special or unexpected. It may be a safari specific thing. — shishirmk, Apr 19 '13 at 00:06
The second line does not do anything, you can safely remove it — Arun P Johny, Apr 19 '13 at 00:16
While the second line does nothing, **sometimes** that syntax is used to to have somewhere to put a breakpoint. Useful if there are no other executable lines . — Jeremy J Starcher, Apr 19 '13 at 00:19

score 5 · Accepted Answer · answered Apr 19 '13 at 00:16

5

The second line does not do anything, you can safely remove it

answered Apr 19 '13 at 00:16

Arun P Johny

1 Answers1