Comparing characters

Question

Suppose I have the following code:

String myString = "Hello";
char firstChar = myString.charAt(0);

I then want to check if firstChar has value "B". I tried

if(myChar == "b")

and

if(myChar.equals("b"))

but none of these work.

What solution could I use?

Thanks in advance!

score 3 · Answer 1 · edited May 23 '17 at 12:28

3

"b" is not char but string to compare char you should write if(myChar == 'b')

Note:

5   means number 
'5' means char 
"5" means string

all are different datatypes.

== compares reference equality. and .equals() tests for value equality.

edited May 23 '17 at 12:28

Community

answered Apr 13 '13 at 19:43

Grijesh Chauhan

@DarioPanada see right hand side of this page **Related**, All are useful for you. Also when you type a question you will find related questions which can save your time to post a question. – Grijesh Chauhan Apr 13 '13 at 19:57

score 0 · Answer 2 · answered Apr 13 '13 at 19:43

0

Use 'B'. Java is case sensitieve, and you neer to compare a char instead of String

answered Apr 13 '13 at 19:43

Rob Audenaerde

score 0 · Answer 3 · answered Apr 13 '13 at 19:45

0

You need to use the char literal by ':

if(myChar == 'b')

quotes(") represent strings. apostrophes(') represent characters

answered Apr 13 '13 at 19:45

Shelef

score 0 · Answer 4 · answered Apr 13 '13 at 19:46

0

Characters work differently than String. You can't call methods on them, but you can compare them using ==.

If you want to compare either case, then you can use this:

if(myChar == 'b' || myChar == 'B')

answered Apr 13 '13 at 19:46

Makoto

4 Answers4