How can I count occurrences of elements that are bigger than a given number in an list?

Question

Let's say I have this list:

a = [1.1, 2, 3.1, 4, 5, 6, 7.2, 8.5, 9.1]

I want to know how many elements are there bigger than 7. The result should be 3. Is there an elegant way to do this in Python? I tried with count but it won't work.

score 18 · Accepted Answer · edited May 23 '17 at 12:08

18

>>> a = [1.1 , 2 , 3.1 , 4 , 5 , 6 , 7.2 , 8.5 , 9.1]
>>> sum(x > 7 for x in a)
3

This uses the fact that bools are ints too.

_{(If you oppose this because you think it isn't clear or pythonic then read this link)}

edited May 23 '17 at 12:08

Community

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answered Apr 02 '13 at 08:51

jamylak

120,885
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Didn't know `True` value can be summed. – John Wang Apr 02 '13 at 09:08
@JohnWang Updated my answer, there's nothing special about `True` and `False` btw, they are just `1` and `0` – jamylak Apr 11 '13 at 05:54

score 2 · Answer 2 · answered Jul 18 '13 at 14:55

2

Even shorter, using numpy:

sum(np.array(a)>7)

answered Jul 18 '13 at 14:55

Noam Peled

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score 0 · Answer 3 · answered Jul 31 '14 at 12:21

write a function that return you count of elements greater than specific number.

def get_max_count(l, num):
    count = 0

    for x in l:
        if x > num:
            count+=1
    return count

l = [1.1, 2, 3.1, 4, 5, 6, 7.2, 8.5, 9.1]
print get_max_count(l=l, num = 7)

How can I count occurrences of elements that are bigger than a given number in an list?

3 Answers3