Is any elegant way to make a list contains some integers to become a list contains some tuples?

Question

I have a list

a = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]

Is any elegant way to make them work in pair? My expected out is

[(1, 2), (3, 4), (5, 6), (7, 8), (9, 10)]

"Is there an elegant way..." In Python, the answer is always yes ;) — rurouniwallace, Mar 31 '13 at 16:25

score 9 · Accepted Answer · answered Mar 31 '13 at 16:24

9

pairs = zip(*[iter(a)]*2)

is a common idiom

answered Mar 31 '13 at 16:24

georg

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Can you add an explanation? – Bibhas Debnath Mar 31 '13 at 16:36

score 6 · Answer 2 · edited Mar 31 '13 at 16:25

6

[(a[2*i], a[2*i+1] ) for i in range(len(a)/2)]

This is of course assuming that len(a) is an even number

edited Mar 31 '13 at 16:25

Grijesh Chauhan

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answered Mar 31 '13 at 16:25

Benjamin

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score 3 · Answer 3 · answered Mar 31 '13 at 16:25

def group(lst, n):
    """group([0,3,4,10,2,3], 2) => [(0,3), (4,10), (2,3)]

    Group a list into consecutive n-tuples. Incomplete tuples are
    discarded e.g.

    >>> group(range(10), 3)
    [(0, 1, 2), (3, 4, 5), (6, 7, 8)]
    """
    return zip(*[lst[i::n] for i in range(n)])

From activestate, a recipe for n-tuples, not just 2-tuples

rurouniwallace · Answer 4 · 2013-03-31T16:40:45.050

1

b = []
for i in range(0,len(a),2):
    b.append((a[i],a[i+1]))
a = b

edited Mar 31 '13 at 16:40

answered Mar 31 '13 at 16:24

rurouniwallace

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score 0 · Answer 5 · answered Mar 31 '13 at 17:39

0

Try it using slices and zip.

>>> a = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
>>> zip(a[::2],a[1::2])
[(1, 2), (3, 4), (5, 6), (7, 8), (9, 10)]

answered Mar 31 '13 at 17:39

pradyunsg

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Is any elegant way to make a list contains some integers to become a list contains some tuples?

5 Answers5