I found an example and was editing it for gas.
extern printf
.global _start
.data
hello:
db "Hello", 0xa, 0
.text
_start:
mov %rdi, hello
mov %rax, 0
call printf
mov %rax, 0
ret
But it doesn't work. What's wrong? What does this mean:
hello:
db "Hello", 0xa, 0
I understand what it scope of memory, but I don't understand this string
db "Hello", 0xa, 0
And here
_start:
mov %rdi, hello
mov %rax, 0
call printf
mov %rax, 0
ret
os: linux (debian). intel 64-bit
It's is the null-byte-terminattor. Well-know as C-string.Such byte at end-of-string say where the string ends. For example,you pass the pointer to your string to call a routine,the routine will understand that the area of such string on memory is from begging a[0](in C terminology) until a[x] == 0 is seen.
All that does is place bytes into the program. The bytes are the characters "Hello", followed by 0xa (which is the line termination), and finally a NULL byte. In C it would be something like "char *hello = "Hello\n";"
At your _start: label, you place the address of the hello label into register %rdi, you place 0 into %rax, and you call the printf function.
The following declares a string with Hello followed by a line feed and null terminator. The null terminator is required for C strings
db "Hello", 0xa, 0
To call printf, you need to pass the parameter on the stack so it would be something like
mov hello, (%esp)
call printf
As far as I know, the convention is mov source, destination. You seem to have coded it the other way round.
