How can I get the name of an object?

Question

Is there any way to get the name of an object in Python? For instance:

my_list = [x, y, z] # x, y, z have been previously defined

for bla in my_list:
    print "handling object ", name(bla) # <--- what would go instead of `name`?
    # do something to bla

Edit: Some context:

What I'm actually doing is creating a list of functions that I can specify by the command line.

I have:

def fun1:
    pass
def fun2
    pass
def fun3:
    pass

fun_dict = {'fun1': fun1,
            'fun2': fun2,
            'fun3': fun3}

I get the name of the function from the commandline and I want to call the relevant function:

func_name = parse_commandline()

fun_dict[func_name]()

And the reason I want to have the name of the function is because I want to create fun_dict without writing the names of the functions twice, since that seems like a good way to create bugs. What I want to do is:

fun_list = [fun1, fun2, fun3] # and I'll add more as the need arises

fun_dict = {}
[fun_dict[name(t) = t for t in fun_list] # <-- this is where I need the name function

This way I only need to write the function names once.

Answer 1

Objects do not necessarily have names in Python, so you can't get the name.

It's not unusual for objects to have a __name__ attribute in those cases that they do have a name, but this is not a part of standard Python, and most built in types do not have one.

When you create a variable, like the x, y, z above then those names just act as "pointers" or "references" to the objects. The object itself does not know what name you are using for it, and you can not easily (if at all) get the names of all references to that object.

Update: However, functions do have a __name__ (unless they are lambdas) so, in that case you can do:

dict([(t.__name__, t) for t in fun_list])

Answer 2

That's not really possible, as there could be multiple variables that have the same value, or a value might have no variable, or a value might have the same value as a variable only by chance.

If you really want to do that, you can use

def variable_for_value(value):
    for n,v in globals().items():
        if v == value:
            return n
    return None

However, it would be better if you would iterate over names in the first place:

my_list = ["x", "y", "z"] # x, y, z have been previously defined

for name in my_list:
    print "handling variable ", name
    bla = globals()[name]
    # do something to bla

 

Answer 3

This one-liner works, for all types of objects, as long as they are in globals() dict, which they should be:

def name_of_global_obj(xx):
    return [objname for objname, oid in globals().items()
            if id(oid)==id(xx)][0]

or, equivalently:

def name_of_global_obj(xx):
    for objname, oid in globals().items():
        if oid is xx:
            return objname

Answer 4

If you are looking to get the names of functions or lambdas or other function-like objects that are defined in the interpreter, you can use dill.source.getname from dill. It pretty much looks for the __name__ method, but in certain cases it knows other magic for how to find the name... or a name for the object. I don't want to get into an argument about finding the one true name for a python object, whatever that means.

>>> from dill.source import getname
>>> 
>>> def add(x,y):
...   return x+y
... 
>>> squared = lambda x:x**2
>>> 
>>> print getname(add)
'add'
>>> print getname(squared)
'squared'
>>> 
>>> class Foo(object):
...   def bar(self, x):
...     return x*x+x
... 
>>> f = Foo()
>>> 
>>> print getname(f.bar)
'bar'
>>> 
>>> woohoo = squared
>>> plus = add
>>> getname(woohoo)
'squared'
>>> getname(plus)
'add'

Answer 5

As others have mentioned, this is a really tricky question. Solutions to this are not "one size fits all", not even remotely. The difficulty (or ease) is really going to depend on your situation.

I have come to this problem on several occasions, but most recently while creating a debugging function. I wanted the function to take some unknown objects as arguments and print their declared names and contents. Getting the contents is easy of course, but the declared name is another story.

What follows is some of what I have come up with.

Return function name

Determining the name of a function is really easy as it has the __name__ attribute containing the function's declared name.

name_of_function = lambda x : x.__name__

def name_of_function(arg):
    try:
        return arg.__name__
    except AttributeError:
        pass`

Just as an example, if you create the function def test_function(): pass, then copy_function = test_function, then name_of_function(copy_function), it will return test_function.

Return first matching object name

1. Check whether the object has a __name__ attribute and return it if so (declared functions only). Note that you may remove this test as the name will still be in globals().

2. Compare the value of arg with the values of items in globals() and return the name of the first match. Note that I am filtering out names starting with '_'.

The result will consist of the name of the first matching object otherwise None.

def name_of_object(arg):
    # check __name__ attribute (functions)
    try:
        return arg.__name__
    except AttributeError:
        pass

    for name, value in globals().items():
        if value is arg and not name.startswith('_'):
            return name

Return all matching object names

• Compare the value of arg with the values of items in globals() and store names in a list. Note that I am filtering out names starting with '_'.

The result will consist of a list (for multiple matches), a string (for a single match), otherwise None. Of course you should adjust this behavior as needed.

def names_of_object(arg):
    results = [n for n, v in globals().items() if v is arg and not n.startswith('_')]
    return results[0] if len(results) is 1 else results if results else None

Answer 6

Here's another way to think about it. Suppose there were a name() function that returned the name of its argument. Given the following code:

def f(a):
    return a

b = "x"
c = b
d = f(c)

e = [f(b), f(c), f(d)]

What should name(e[2]) return, and why?

Answer 7

Use a reverse dict.

fun_dict = {'fun1': fun1,
            'fun2': fun2,
            'fun3': fun3}

r_dict = dict(zip(fun_dict.values(), fun_dict.keys()))

The reverse dict will map each function reference to the exact name you gave it in fun_dict, which may or may not be the name you used when you defined the function. And, this technique generalizes to other objects, including integers.

For extra fun and insanity, you can store the forward and reverse values in the same dict. I wouldn't do that if you were mapping strings to strings, but if you are doing something like function references and strings, it's not too crazy.

Answer 8

Note that while, as noted, objects in general do not and cannot know what variables are bound to them, functions defined with def do have names in the __name__ attribute (the name used in def). Also if the functions are defined in the same module (as in your example) then globals() will contain a superset of the dictionary you want.

def fun1:
  pass
def fun2:
  pass
def fun3:
  pass

fun_dict = {}
for f in [fun1, fun2, fun3]:
  fun_dict[f.__name__] = f

Answer 9

And the reason I want to have the name of the function is because I want to create fun_dict without writing the names of the functions twice, since that seems like a good way to create bugs.

For this purpose you have a wonderful getattr function, that allows you to get an object by known name. So you could do for example:

funcs.py:

def func1(): pass
def func2(): pass

main.py:

import funcs
option = command_line_option()
getattr(funcs, option)()

Answer 10

I know This is late answer.

1. To get func name , you can use func.__name__
2. To get the name of any python object that has no name or __name__ method. You can iterate over its module members.

Ex:.

# package.module1.py

obj = MyClass()



# package.module2.py
import importlib
def get_obj_name(obj):
   mod = Obj.__module__ # This is necessary to 
   module = module = importlib.import_module(mod)
   for name, o in module.__dict__.items():
      if o == obj:
         return name

Performance note: don't use it in large modules.

Answer 11

Variable names can be found in the globals() and locals() dicts. But they won't give you what you're looking for above. "bla" will contain the value of each item of my_list, not the variable.

Answer 12

Generally when you are wanting to do something like this, you create a class to hold all of these functions and name them with some clear prefix cmd_ or the like. You then take the string from the command, and try to get that attribute from the class with the cmd_ prefixed to it. Now you only need to add a new function/method to the class, and it's available to your callers. And you can use the doc strings for automatically creating the help text.

As described in other answers, you may be able to do the same approach with globals() and regular functions in your module to more closely match what you asked for.

Something like this:

class Tasks:
    def cmd_doit(self):
        # do it here

func_name = parse_commandline()
try:
    func = getattr('cmd_' + func_name, Tasks())
except AttributeError:
    # bad command: exit or whatever
func()

Answer 13

I ran into this page while wondering the same question.

As others have noted, it's simple enough to just grab the __name__ attribute from a function in order to determine the name of the function. It's marginally trickier with objects that don't have a sane way to determine __name__, i.e. base/primitive objects like basestring instances, ints, longs, etc.

Long story short, you could probably use the inspect module to make an educated guess about which one it is, but you would have to probably know what frame you're working in/traverse down the stack to find the right one. But I'd hate to imagine how much fun this would be trying to deal with eval/exec'ed code.

% python2 whats_my_name_again.py
needle => ''b''
['a', 'b']
[]
needle => '<function foo at 0x289d08ec>'
['c']
['foo']
needle => '<function bar at 0x289d0bfc>'
['f', 'bar']
[]
needle => '<__main__.a_class instance at 0x289d3aac>'
['e', 'd']
[]
needle => '<function bar at 0x289d0bfc>'
['f', 'bar']
[]
%

whats_my_name_again.py:

#!/usr/bin/env python

import inspect

class a_class:
    def __init__(self):
        pass

def foo():
    def bar():
        pass

    a = 'b'
    b = 'b'
    c = foo
    d = a_class()
    e = d
    f = bar

    #print('globals', inspect.stack()[0][0].f_globals)
    #print('locals', inspect.stack()[0][0].f_locals)

    assert(inspect.stack()[0][0].f_globals == globals())
    assert(inspect.stack()[0][0].f_locals == locals())

    in_a_haystack = lambda: value == needle and key != 'needle'

    for needle in (a, foo, bar, d, f, ):
        print("needle => '%r'" % (needle, ))
        print([key for key, value in locals().iteritems() if in_a_haystack()])
        print([key for key, value in globals().iteritems() if in_a_haystack()])


foo()

Answer 14

You define a class and add the Unicode private function insert the class like

class example:
  def __init__(self, name):
    self.name = name

  def __unicode__(self):
    return self.name

Of course you have to add extra variable self.name which is the name of the object.

Answer 15

Here is my answer, I am also using globals().items()

    def get_name_of_obj(obj, except_word = ""):

        for name, item in globals().items():
            if item == obj and name != except_word:
                return name

I added except_word because I want to filter off some word used in for loop. If you didn't add it, the keyword in for loop may confuse this function, sometimes the keyword like "each_item" in the following case may show in the function's result, depends on what you have done to your loop.

eg.

    for each_item in [objA, objB, objC]:
        get_name_of_obj(obj, "each_item")

eg.

    >>> objA = [1, 2, 3]
    >>> objB = ('a', {'b':'thi is B'}, 'c')
    >>> for each_item in [objA, objB]:
    ...     get_name_of_obj(each_item)
    ...
    'objA'
    'objB'
    >>>
    >>>
    >>> for each_item in [objA, objB]:
    ...     get_name_of_obj(each_item)
    ...
    'objA'
    'objB'
    >>>
    >>>
    >>> objC = [{'a1':'a2'}]
    >>>
    >>> for item in [objA, objB, objC]:
    ...     get_name_of_obj(item)
    ...
    'objA'
    'item'  <<<<<<<<<< --------- this is no good
    'item'
    >>> for item in [objA, objB]:
    ...     get_name_of_obj(item)
    ...
    'objA'
    'item'     <<<<<<<<--------this is no good
    >>>
    >>> for item in [objA, objB, objC]:
    ...     get_name_of_obj(item, "item")
    ...
    'objA'
    'objB'  <<<<<<<<<<--------- now it's ok
    'objC'
    >>>

Hope this can help.

Answer 16

Python has names which are mapped to objects in a hashmap called a namespace. At any instant in time, a name always refers to exactly one object, but a single object can be referred to by any arbitrary number of names. Given a name, it is very efficient for the hashmap to look up the single object which that name refers to. However given an object, which as mentioned can be referred to by multiple names, there is no efficient way to look up the names which refer to it. What you have to do is iterate through all the names in the namespace and check each one individually and see if it maps to your given object. This can easily be done with a list comprehension:

[k for k,v in locals().items() if v is myobj]

This will evaluate to a list of strings containting the names of all local "variables" which are currently mapped to the object myobj.

>>> a = 1
>>> this_is_also_a = a
>>> this_is_a = a
>>> b = "ligma"
>>> c = [2,3, 534]
>>> [k for k,v in locals().items() if v is a]

['a', 'this_is_also_a', 'this_is_a']

Of course locals() can be substituted with any dict that you want to search for names that point to a given object. Obviously this search can be slow for very large namespaces because they must be traversed in their entirety.

Answer 17

Based on what it looks like you're trying to do you could use this approach.

In your case, your functions would all live in the module foo. Then you could:

import foo

func_name = parse_commandline()
method_to_call = getattr(foo, func_name)
result = method_to_call()

Or more succinctly:

import foo

result = getattr(foo, parse_commandline())()

Answer 18

Hi there is one way to get the variable name that stores an instance of a class is to use

locals()

function, it returns a dictionary that contains the variable name as a string and its value