I have a data structure like:
[ ["id1", 123], ["id2", 1], ["id3", 6] ]
and I would like to ordered it (descendingly) according to the second variable, like this:
[ ["id1", 123], ["id3", 6], ["id2", 1] ]
I could write up a little function for doing that, but I am almost sure there's a cool one liner way of doing it, isn't there? Thanks.
You can do it using sorted and itemgetter:
>>> a = [ ["id1", 123], ["id2", 1], ["id3", 6] ]
>>> from operator import itemgetter
>>> sorted(a, key=itemgetter(1), reverse=True)
[['id1', 123], ['id3', 6], ['id2', 1]]
If you purely wanted a one-liner (no import), then you can lambda it:
>>> sorted(a, key=lambda L: L[1], reverse=True)
