sorting of an array alphabetically in objective-c

Question

I want to sort my array alphabetically in objective-c. I have implemented it this way.

//Sorting of the Array
NSArray *sortedArray = [arrName sortedArrayUsingComparator:^(Cars *firstObject, Cars *secondObject) {
    return [firstObject.str_name compare:secondObject.str_name];
}];
arrName =[NSMutableArray arrayWithArray:sortedArray];

The problem is all the numbers appear followed by captial letters words followed by lowercase letters items...

I want it to appear alphabetically-> meaning to say that the capital letters and lowercase letters maybe mixed.

rmaddy · Accepted Answer · 2013-02-19T04:14:44.327

14

Replace compare: with caseInsensitiveCompare:.

Since arrName is mutable, use the 'sortUsingComparator' method instead. It will sort the mutable array in place without creating a new array.

[arrName sortUsingComparator:^(Cars *firstObject, Cars *secondObject) {
    return [firstObject.str_name caseInsensitiveCompare:secondObject.str_name];
}];

edited Feb 19 '13 at 04:14

answered Feb 19 '13 at 03:45

rmaddy

307,833
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then am i right to say that sortedArray has to become of type NSMutableArray? – lakshmen Feb 19 '13 at 03:58
No, you don't need `sortedArray`. – rmaddy Feb 19 '13 at 03:58
have i done it correctly? – lakshmen Feb 19 '13 at 04:01
Almost. See my update. – rmaddy Feb 19 '13 at 04:08
If anyone is using set of characters other than latin they should use comparator: `localizedCaseInsensitiveCompare` – Marek J. Jun 12 '19 at 12:01

score -1 · Answer 2 · answered Feb 19 '13 at 03:49

-1

try this,

NSArray *array=[[NSArray alloc]initWithObjects:@"Object1",@"object1", nil];      
array =[array sortedArrayUsingSelector:@selector(localizedCaseInsensitiveCompare:)];
NSLog(@"%@",array);

answered Feb 19 '13 at 03:49

Ravindhiran

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This won't work. It's not an array of strings, it's an array of objects and the sort is on a property of the objects. – rmaddy Feb 19 '13 at 03:52

sorting of an array alphabetically in objective-c

2 Answers2