Intent and start activity from string

Question

I have a little problem. I want to start activity but in something other way. I know that

Intent i = new Intent(this, ActivityTwo.class);

initialize intent and after that I can startActivity. But I want do something like that:

Intent i = new Intent(this, MyString.class);

I have no nameActivity.class, but I want change on string.class. How I can start activity when I have string name of class?

What exactly is the scenario? Are you trying to start an activity based on some STRING value which will be used as the name for the Activity to be launched? — Anukool, Feb 13 '13 at 09:28
http://stackoverflow.com/questions/5754855/how-can-i-start-a-new-android-activity-using-a-string — baboo, Feb 13 '13 at 09:28
When you have for example ActivityFirst.class I want to have string instead ActivityFirst and this is necessary — user1302569, Feb 13 '13 at 09:29
Possible duplicate of [How can I start a new android activity using a string?](http://stackoverflow.com/questions/5754855/how-can-i-start-a-new-android-activity-using-a-string) — ThomasW, Feb 27 '17 at 10:41

score 8 · Accepted Answer · answered Feb 13 '13 at 09:28

8

Try this: startActivity(this, Class.forName(yourStringClass));

answered Feb 13 '13 at 09:28

PaNaVTEC

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The constructor Intent(TabsGenerator, Class) is undefined too :) – user1302569 Feb 13 '13 at 09:33
try the casting: `(Class extends Activity>)Class.forName("YourClass")` – PaNaVTEC Feb 13 '13 at 09:36
Intent intent = new Intent(TabsGenerator.this, (Class extends Activity>)Class.forName(StringClassname)); doesn't work too. The same error – user1302569 Feb 13 '13 at 09:44
1

Are you writting the full class name? With package. "com.youpackge.YourClass" Also you can try with: intent.setClassName(context,target); – PaNaVTEC Feb 13 '13 at 09:50
try with new Intent().setClassName – PaNaVTEC Feb 13 '13 at 09:54

score 6 · Answer 2 · answered Feb 13 '13 at 09:29

6

Here is a code by which you can start activity using the name of the activity

Class<?> c = null;
if(StringClassname != null) {
    try {
        c = Class.forName(StringClassname );
    } catch (ClassNotFoundException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }
}
Intent intent = new Intent(mail.this, c);
startActivity(intent);

Here class name will be full name of the class with the package name. For example if your package name will be x.y.z and if you have Activity name called A then the full name of the Activity A will be x.y.z.A.

answered Feb 13 '13 at 09:29

jlopez

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The constructor Intent(TabsGenerator, Class) is undefined – user1302569 Feb 13 '13 at 09:35
Change this: `Intent(TabsGenerator, Class);` to `Intent(TabsGenerator.this, Class;` – jlopez Feb 13 '13 at 09:37

score 4 · Answer 3 · edited Jan 18 '14 at 05:36

4

You can look up a Class by name using Class.forName("MyString")

edited Jan 18 '14 at 05:36

Bhavin Nattar

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answered Feb 13 '13 at 09:28

Clyde

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score 2 · Answer 4 · answered Sep 24 '16 at 11:54

2

Just use....

  Intent intent = new Intent().setClassName(activity,"packageName"+"className");
  startActivity(intent);

answered Sep 24 '16 at 11:54

Nilesh

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score 1 · Answer 5 · edited Feb 13 '13 at 09:52

1

Class<?> c =Class.forName("YOUR STRING" );
Intent intent = new Intent(FirstActivity.this, c);
startActivity(intent);

edited Feb 13 '13 at 09:52

René Höhle

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answered Feb 13 '13 at 09:31

Anukool

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The constructor Intent(TabsGenerator, Class) is undefined – user1302569 Feb 13 '13 at 09:32
1

Forgot to mention- the class name should be the fully qualified class name. Suppose the package name is com.something and the String is "THESTRING" then the fully qualified name will be - com.something.THESTRING .. Hope this helps – Anukool Feb 13 '13 at 09:52
@Anukool : Please Edit your answer and put this comment in it. – Kishor Pawar May 27 '15 at 11:15

Intent and start activity from string

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