How to convert boost::uintmax_t to std::string

Question

boost::filesystem::file_size() returns boost::uintmax_t. So, How to convert boost::uintmax_t to std::string?

I'm guessing both `std::to_string` and `boost::lexical_cast` do the job. — chris, Jan 29 '13 at 08:14
Some suggestions here: http://stackoverflow.com/questions/10516196/append-an-int-to-a-stdstring/10516313#10516313 — hmjd, Jan 29 '13 at 08:15
std::to_string not works but boost::lexical_cast works. thank you experts! — Nayana Adassuriya, Jan 29 '13 at 09:40

score 1 · Accepted Answer · answered Jan 29 '13 at 08:26

Well, you can use some simple approach like:

boost::lexical_cast<std::string>(size);

Or manually using the stringstream:

static_cast<std::stringstream>(std::stringstream() << size).str()

The operator for numbers is a member, so it should work on temporary even in C++03; some other overloads are free functions and in C++03 those don't accept temporary, but you can use std::stringstream().flush(), which returns lvalue reference and than all operator<< overloads work.

But it's not just plain number. It's file size. So it's quite likely you should be rounding it and handling kB/MB/GB/KiB/MiB/GiB units. In which case have a look at libkibi.

How to convert boost::uintmax_t to std::string

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