How can I callback AJAX success function after successful Spring Security login?

Question

I have clients that issue AJAX calls. These calls reference URLs that are protected by Spring Security on the sever side. If the user's session has timed out, I have a login form popup in a lightbox. After the user has successfully logged in, I would like the client to re-execute AJAX call.

Here's an example of the client side code that makes an AJAX call:

function handleSearchClick(evt) {
    var setupOptions = { 
        success: loadSearch,
        type: "POST",
        dataType: "json",            
        url:   "../search.ajax",
        error: handleError, // how can I pass callback info i.e. I want to be able to execute $("#searchForm").ajaxSubmit(setupOptions); from handleError? 
        timeout: 50000
    };                
    $("#searchForm").ajaxSubmit(setupOptions);
}

When the authentication fails, the server returns a 401 which results in the client calling handleError. Is it possible to pass a callback function to handleError? I would want the callback to re-execute

$("#searchForm").ajaxSubmit(setupOptions);

I have seen solutions to this problem where the server returns a success response on AJAX calls that have a session timed out. Then, the success function looks for something in the response to know the session timeout. The client then stores a callback function there. I prefer though to handle this in the error function.

Thanks for the answer. However, in the code below "But you could do the following", I'm not sure how handleError will be able to call $("#searchForm").ajaxSubmit(setupOptions). Could you please edit to provide more details on how this would be done? — James, Jan 15 '13 at 23:54

score 3 · Accepted Answer · answered Jan 16 '13 at 03:00

3

The request executed by

$("#searchForm").ajaxSubmit(setupOptions);

can be re-executed in the handleError function by calling

$.ajax(this);

There is no need to pass in a callback function to re-execute:

$("#searchForm").ajaxSubmit(setupOptions);

answered Jan 16 '13 at 03:00

James

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score 2 · Answer 2 · edited May 23 '17 at 11:56

I've mentioned it here: How to send a form without refreshing the page?

It's the way of having a callback for the error handler.

$.ajax({
    url: siteUrl + 'fetch/search',
    type: "POST",
    data: formData,
    success: function(data) {
      .....
    },
    error:function(x,e){
        if(x.status==0){
            alert('You are offline!!\n Please Check Your Network.');
        }else if(x.status==404){
            alert('Requested URL not found.');
        }else if(x.status==500){
            alert('Internel Server Error.');
        }else if(e=='parsererror'){
            alert('Error.\nParsing JSON Request failed.');
        }else if(e=='timeout'){
            alert('Request Time out.');
        }else {
            alert('Unknow Error.\n'+x.responseText);
        }
    }
});

But you could do the following

function handleSearchClick(evt) {
    var setupOptions = { 
        success: loadSearch,
        type: "POST",
        dataType: "json",            
        url:   "../search.ajax",
        error: handleError(x,e), // this should do it
        timeout: 50000
    };                
    $("#searchForm").ajaxSubmit(setupOptions);
}

error needs to be a reference to a function. However, in last code snippet you have an invocation of a function. — James, Jan 15 '13 at 23:59

Jeffery To · Answer 3 · 2013-01-16T11:33:07.020

2

Closures to the rescue:

function handleSearchClick(evt) {
    var setupOptions = {
        success: loadSearch,
        type: "POST",
        dataType: "json",
        url: "../search.ajax",
        timeout: 50000
    };
    setupOptions.error = handleError(setupOptions);
    $("#searchForm").ajaxSubmit(setupOptions);
}

function handleError(setupOptions) {
    return function () {
        // handle error

        // then re-submit
        $("#searchForm").ajaxSubmit(setupOptions);
    };
}

Note that this creates a reference loop (setupOptions has a reference to the error function returned by handleError, the error function has a reference to setupOptions), but this should be easily garbage-collected by any decent browser.

edited Jan 16 '13 at 11:33

answered Jan 16 '13 at 11:19

Jeffery To

11,698
1
26
42

Thanks! This is a correct solution to the question. I think the built in jquery call $.ajax(this) will be better for handling errors from multiple types of request in a generic way. I did not realize that functionality existed until after posting my question. I gave +1 to your answer as it would great way to do this and would be my choice if the jquery call did not exist. – James Jan 18 '13 at 23:09

How can I callback AJAX success function after successful Spring Security login?

3 Answers3