javascript: for each item in array: create div, move div and remove div after timeperiod

Question

I have a list of names; and I want to display these names one by one. The name should apear in the top of a container, subsequently move to the bottom, and then disapear. In the mean time, the next name should have appeared in the top of the container, started moving,..., etc.

I'm not that for yet: I still need to create the code which makes the divs move; I'll do that later and it is maybe easier to create a separate function for that.

I realize very well the way in which I'm trying to achieve this is very likely too cumbersome, but I'm just a beginner... So for I made:

function myNamesFunction() {} {

  var y = 0;
  for (y = 0; y < document.getElementById("namelistID").getElementsByTagName('div').length;y++)

 {

 var vinden2 = document.getElementById("namelistID").getElementsByTagName('div')[y];

 {

  var div = document.createElement("div");
  div.innerHTML = (document.getElementById("namelistID").getElementsByTagName('div')[y].innerHTML);

  setTimeout(function () {
    document.getElementById("namecontentbox").appendChild(div)[y];
  }, 0000);
  setTimeout(function () {
    document.getElementById("namecontentbox").removeChild(div)[y];
  }, 2000);


 }

 }

}

The Html code is:

<div id="namelistID" style="display: none;">
  <div class="nameofperson">Person1</div>
  <div class="nameofperson">Person2</div>
  <div class="nameofperson">Person3</div>
  <div class="nameofperson">Person4</div>
</div>
<div id="namecontentbox"></div>

The problem is now that since I added the "settimeout", only the last item from the array seems to be created and removed. How can I start with the first, and then let each item appear and disappear?

(Any other advice on how to continue (or restart...) is very welcome too)

possible duplicate of [loop through a javascript object](http://stackoverflow.com/questions/11581742/loop-through-a-javascript-object) — Denys Séguret, Jan 06 '13 at 15:37

Denys Séguret · Accepted Answer · 2013-01-06T17:45:47.433

2

That's a classical problem, due to y's value changing by the time the function you give to setTimeout is called.

The classical solution is to protect y with a closure in your loop :

  for (y = 0; y < document.getElementById("namelistID").getElementsByTagName('div').length;y++) {
    (function(y){
      // use y
    })(y);
  }

This function is the scope of the new y variable and, as it's immediately executed, it keeps protected the value y had at this time.

If you want the timeout to be executed one after the other, and not all at the same time, increment the time :

  setTimeout(function () {
    document.getElementById("namecontentbox").removeChild(div)[y];
  }, 2000*(y+1));

edited Jan 06 '13 at 17:45

answered Jan 06 '13 at 15:34

Denys Séguret

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Ok, thanks that indeed helps to get the right items, but they are added all at once. It doesn't help to put a timeout right after the (function(y){ – user1843471 Jan 06 '13 at 17:14
If you want the timeouts to be executed at incremented times, and not all 2 seconds after the loop, you have to pass different delays. See updated answer. – Denys Séguret Jan 06 '13 at 17:46
Yes, that's it. Thank you! – user1843471 Jan 07 '13 at 11:53

javascript: for each item in array: create div, move div and remove div after timeperiod

1 Answers1