Javascript RegExp to find all occurences of a a quoted word in an array

Question

Given I have a sentence:

var testsentence = 'This "is" a wonderful "sentence" to "test" "stuff"';

How can I get an array like that?

var testarray = [ "is", "sentence", "test", "stuff" ]

UPDATE

I am using the Chromium console to try your response, but so far all the responses return:

[""is"", ""sentence"", ""test"", ""stuff""]

I don't want to have quotes in my matches.

score 2 · Accepted Answer · edited May 23 '17 at 12:30

2

To capture the quoted text, but not the quotes...note match won't return groups with the g modifier (see this question), so loop over the matches with something like:

var testsentence = 'This "is" a wonderful "sentence" to "test" "stuff"';
var pattern = /"([^"]+)"/g;
var match;
var testarray = [];
while(match = pattern.exec(testsentence)) {
    testarray.push(match[1]);
}

edited May 23 '17 at 12:30

Community

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answered Dec 12 '12 at 16:48

Anson

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Is this really the quickest way? Hoped there was something simpler. – user1680104 Dec 12 '12 at 17:15
Not sure....if you don't save the regex in `var pattern` then it won't iterate matches during each loop. If you don't mind keeping the quotes, then others' solutions are more brief. – Anson Dec 12 '12 at 17:28

Bergi · Answer 2 · 2012-12-12T17:19:34.440

1

(testsentence.match(/"\w+"/g) || []).map(function(w) {
    return w.slice(1, -1);
});

edited Dec 12 '12 at 17:19

answered Dec 12 '12 at 16:26

Bergi

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Only match quoted words. `He said "well, I won't do it" abruptly` wouldn't match. – Clement Herreman Dec 12 '12 at 16:30
@ClementHerreman: should that match? I dont think so. For a solution that does this see burning_LEGION's and RicardoLohmann's answers. – Bergi Dec 12 '12 at 16:32
But I would have the quotes in the matches. – user1680104 Dec 12 '12 at 17:09
@user1680104: You'd have that with nearly all matching solutions. Just remove them from the results. – Bergi Dec 12 '12 at 17:20
Thank you. So there really isn't something simpler? What if I had a similar task with a non-static pattern before? like `/sequencepart\d+"(stufftofind)"/` – user1680104 Dec 12 '12 at 17:28
Exactly. You'd have to use the `exec()` loop (see Ansons' answer) or matching + removing quotes, as JavaScript does not support [lookbehind regexes](http://www.regular-expressions.info/lookaround.html) as in `/(?<=")\w+(?=")/g` – Bergi Dec 12 '12 at 17:38
How would I do something like `/sequencepart\d+"?(stufftofind)"?/` using Anson's answer? Is that possible? – user1680104 Dec 12 '12 at 23:20
I created [a new question](http://stackoverflow.com/questions/13850492/regular-expression-to-find-complex-markers), because it is. – user1680104 Dec 12 '12 at 23:31
@user1680104: Does Anson's code not work with that? It seems to be exactly the answer. – Bergi Dec 13 '12 at 00:12

score 1 · Answer 3 · answered Dec 12 '12 at 16:27

1

testsentence.match(/"([^"\s])+"/g)

should return everything that is quoted, and avoid things like ""

answered Dec 12 '12 at 16:27

Clement Herreman

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No need for the grouping operator around the character class, btw – Bergi Dec 12 '12 at 17:21

score 1 · Answer 4 · answered Dec 12 '12 at 16:33

1

testsentence.match(/"[^"]+"/g);

demo

answered Dec 12 '12 at 16:33

Ricardo Alvaro Lohmann

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But it has quotes in the array – user1680104 Dec 12 '12 at 17:10

score 0 · Answer 5 · answered Dec 12 '12 at 16:29

0

return testsentence.match(/".+?"/g);

answered Dec 12 '12 at 16:29

burning_LEGION

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Javascript RegExp to find all occurences of a a quoted word in an array

5 Answers5