how to get receipt num in sequence order like this AB0810001

Question

AB is an receipt code should be constant next (08 todays date) and 10001 is receipt num?

possible duplicate of [MySQL Auto Increment Custom Values](http://stackoverflow.com/questions/5228408/mysql-auto-increment-custom-values) — Madara's Ghost, Oct 08 '12 at 09:31

score 1 · Answer 1 · answered Oct 08 '12 at 09:31

1

$prefix      = 'AB';
$today       =  date("d");
$receipt_num = '10001';//from db value

echo $prefix.$today.$receipt_num;

answered Oct 08 '12 at 09:31

iLaYa ツ

score 0 · Answer 2 · answered Oct 08 '12 at 09:33

0

If you're sure there always will be 4 characters in front of the receipt number, you could of course use substr:

$data = 'AB0810001';
$receipt = substr($data, 4);
echo $receipt;  // will output 10001

answered Oct 08 '12 at 09:33

Havelock

score 0 · Answer 3 · answered Oct 08 '12 at 09:34

0

If you mean how to get those chunks from that string this should do it:

var str = 'AB0810001';
var result = str.match(/([A-Z]{2})(\d{2})(\d{5})/);
result.shift();
console.log(result); //=> ['AB', '08', '10001']

answered Oct 08 '12 at 09:34

elclanrs

3 Answers3