How can I know if I'm calling a jQuery function?

Question

I've some libraries on my website, that are using $ as variable/function. I made them separate with :

jQuery(document).ready(function ($) {
    codeThatWillUseJquery($);
});

but in fact, I think there are somethings wrong. in fact :

function codeThatWillUseJquery($)
{
    console.log($('#myId').index());
}

it returns always -1, on every element. So I think there is some incompatibility in the code.

How can I know if $('#myId').index() call the jQuery's .index() function? Is there a way?

Why not do something like `var $jq = jQuery.noConflict()` if there is another `$`-namespace? — Johan, Oct 04 '12 at 07:51
go to jQuery Source File watch the .index() function than type on Chrome Console $('#myId').index() without ; and compare snipets. — Rosmarine Popcorn, Oct 04 '12 at 07:51
$('#myId').index() returns TypeError: undefined is not a function ? — markzzz, Oct 04 '12 at 07:57

score 2 · Accepted Answer · edited May 23 '17 at 12:18

2

you should use obj instanceof jQuery

edited May 23 '17 at 12:18

Community

answered Oct 04 '12 at 07:52

Pragnesh Chauhan

uhm, so `$('#myId').index() instanceof jQuery`? It returns false :O – markzzz Oct 04 '12 at 07:57
like `$('#myId') instanceof jQuery` – Pragnesh Chauhan Oct 04 '12 at 08:04

1 Answers1