More declarative PHP: array conversion

Question

I have an array of class objects:

class Foo
{
    public $A;
    public $B;
    public $C;
}

I need a new array of C fields. Is there a way to convert the array without explicit loops? Hate that after C#.

// Explicit conversion:
foreach ($arr as $item)
{
    $Cs[] = $item->C;
}

Regards,

btw: in C# you can use linq, so you don't have to use explicit loops.. — Philipp, Oct 02 '12 at 10:32

Matěj Koubík · Accepted Answer · 2012-10-02T10:28:52.527

8

$Cs = array_map(function($item) {
    return $item->C;
}, $arr);

edited Oct 02 '12 at 10:28

answered Oct 02 '12 at 10:28

Matěj Koubík

In PHP < 5.3 you can use named function with array_map('function_name', $arr); – Matěj Koubík Oct 02 '12 at 10:31
1

Or `create_function()`, but in my opinion PHP5.3 should be mainstream nowadays. – KingCrunch Oct 02 '12 at 10:32
Not a lambda syntax, but at least requires no external functions. Thank you. – noober Oct 02 '12 at 12:13

score 0 · Answer 2 · answered Oct 02 '12 at 10:34

0

I believe you can use get_object_vars.

$arr = get_object_vars(new Foo());
var_dump($arr); // should give Array(3) { "A"=>NULL, "B"=>NULL, "C"=>NULL }

answered Oct 02 '12 at 10:34

Prasanth

Yep, but $arr is array of Foo, not a single instance. Also, I'll have to filter the resulting array from As and Bs. – noober Oct 02 '12 at 10:37

2 Answers2