Regex pattern for "contains not only spaces"

Question

Please tell me which pattern I need to use if field must not contain only spaces.

"\s+" means "one or more whitespaces of any kind". – duffymo Sep 24 '12 at 15:48 — duffymo, Sep 24 '12 at 15:48
Case is so important. Corrected. – duffymo Sep 24 '12 at 15:51 — duffymo, Sep 24 '12 at 15:51
nobody understand my question.. – Kirill Bazarov Sep 25 '12 at 08:33 — Kirill Bazarov, Sep 25 '12 at 08:33

score 17 · Accepted Answer · answered Sep 24 '12 at 15:47

17

Why need to use regex?

str.trim().isEmpty()

answered Sep 24 '12 at 15:47

xdazz

ok i did it a little bit another way - str.replace(" ","") and then isEmpty() – Kirill Bazarov Sep 25 '12 at 08:33

score 12 · Answer 2 · answered Sep 24 '12 at 15:49

12

You must use this pattern.

.*[^ ].*

It can be anything but not only spaces.

answered Sep 24 '12 at 15:49

Caner Korkmaz

In javascript this regex does not allow any spaces at all – Niklas Jun 20 '17 at 14:12

score 2 · Answer 3 · answered Sep 24 '12 at 15:47

2

assuming you mean any whitespace, not just spaces, \S will work.

Cfr every dev's must-have friend, The regex cheat sheet

answered Sep 24 '12 at 15:47

Joeri Hendrickx

field could be "Hi i am" but could not be " ". It can contain spaces but not only spaces – Kirill Bazarov Sep 24 '12 at 15:48
@KirillBazarov: If your string matches \S it means that it has at least one character that is not a whitespace. It still can contain whitespaces. – Daniel Hilgarth Sep 24 '12 at 15:50
@DanielHilgarth indeed. I think that's what the OP is asking. – Joeri Hendrickx Sep 24 '12 at 15:55

Susampath · Answer 4 · 2017-10-13T09:27:02.497

0

This is much simple .If you are using java just code this. As example:-

classVariable.getname().trim().equal("")

by this you can check whether that variable contains only spaces.

edited Oct 13 '17 at 09:27

answered Oct 13 '17 at 05:33

Susampath

score 0 · Answer 5 · edited Oct 30 '18 at 12:08

I've got one it seems heavy but it's not that hard to implement

patern with no blank :

^[patern]*[patern without space][patern]*$

Exemple:

-patern: a-zA-ZÀ-ÿ '-

(note that it allows spaces)

[a-zA-ZÀ-ÿ '-]

with no blank =

^[a-zA-ZÀ-ÿ '-]*[a-zA-ZÀ-ÿ'-][a-zA-ZÀ-ÿ '-]*

Of course If you don't allow space at all you don't need to do that.

You can test yours on https://regexr.com/

5 Answers5