Only using @JsonIgnore during serialization, but not deserialization

Question

I have a user object that is sent to and from the server. When I send out the user object, I don't want to send the hashed password to the client. So, I added @JsonIgnore on the password property, but this also blocks it from being deserialized into the password that makes it hard to sign up users when they don't have a password.

How can I only get @JsonIgnore to apply to serialization and not deserialization? I'm using Spring JSONView, so I don't have a ton of control over the ObjectMapper.

Things I've tried:

1. Add @JsonIgnore to the property
2. Add @JsonIgnore on the getter method only

Answer 1

Exactly how to do this depends on the version of Jackson that you're using. This changed around version 1.9, before that, you could do this by adding @JsonIgnore to the getter.

Which you've tried:

Add @JsonIgnore on the getter method only

Do this, and also add a specific @JsonProperty annotation for your JSON "password" field name to the setter method for the password on your object.

More recent versions of Jackson have added READ_ONLY and WRITE_ONLY annotation arguments for JsonProperty. So you could also do something like:

@JsonProperty(access = JsonProperty.Access.WRITE_ONLY)
private String password;

Docs can be found here.

Answer 2

In order to accomplish this, all that we need is two annotations:

1. @JsonIgnore
2. @JsonProperty

Use @JsonIgnore on the class member and its getter, and @JsonProperty on its setter. A sample illustration would help to do this:

class User {

    // More fields here
    @JsonIgnore
    private String password;

    @JsonIgnore
    public String getPassword() {
        return password;
    }

    @JsonProperty
    public void setPassword(final String password) {
        this.password = password;
    }
}

Answer 3

Since version 2.6: a more intuitive way is to use the com.fasterxml.jackson.annotation.JsonProperty annotation on the field:

@JsonProperty(access = Access.WRITE_ONLY)
private String myField;

Even if a getter exists, the field value is excluded from serialization.

JavaDoc says:

/**
 * Access setting that means that the property may only be written (set)
 * for deserialization,
 * but will not be read (get) on serialization, that is, the value of the property
 * is not included in serialization.
 */
WRITE_ONLY

In case you need it the other way around, just use Access.READ_ONLY.

Answer 4

In my case, I have Jackson automatically (de)serializing objects that I return from a Spring MVC controller (I am using @RestController with Spring 4.1.6). I had to use com.fasterxml.jackson.annotation.JsonIgnore instead of org.codehaus.jackson.annotate.JsonIgnore, as otherwise, it simply did nothing.

Answer 5

Another easy way to handle this is to use the argument allowSetters=truein the annotation. This will allow the password to be deserialized into your dto but it will not serialize it into a response body that uses contains object.

example:

@JsonIgnoreProperties(allowSetters = true, value = {"bar"})
class Pojo{
    String foo;
    String bar;
}

Both foo and bar are populated in the object, but only foo is written into a response body.

Answer 6

"user": {
        "firstName": "Musa",
        "lastName": "Aliyev",
        "email": "klaudi2012@gmail.com",
        "passwordIn": "98989898", (or encoded version in front if we not using https)
        "country": "Azeribaijan",
        "phone": "+994707702747"
    }

---

@CrossOrigin(methods=RequestMethod.POST)
@RequestMapping("/public/register")
public @ResponseBody MsgKit registerNewUsert(@RequestBody User u){

        root.registerUser(u);

    return new MsgKit("registered");
}  

---

@Service
@Transactional
public class RootBsn {

    @Autowired UserRepository userRepo;

    public void registerUser(User u) throws Exception{

        u.setPassword(u.getPasswordIn());
        //Generate some salt and  setPassword (encoded -  salt+password)
        User u=userRepo.save(u);

        System.out.println("Registration information saved");
    }

}

---

    @Entity        
@JsonIgnoreProperties({"recordDate","modificationDate","status","createdBy","modifiedBy","salt","password"})
                    public class User implements Serializable {
                        private static final long serialVersionUID = 1L;

                        @Id
                        @GeneratedValue(strategy=GenerationType.AUTO)
                        private Long id;

                        private String country;

                        @Column(name="CREATED_BY")
                        private String createdBy;

                        private String email;

                        @Column(name="FIRST_NAME")
                        private String firstName;

                        @Column(name="LAST_LOGIN_DATE")
                        private Timestamp lastLoginDate;

                        @Column(name="LAST_NAME")
                        private String lastName;

                        @Column(name="MODIFICATION_DATE")
                        private Timestamp modificationDate;

                        @Column(name="MODIFIED_BY")
                        private String modifiedBy;

                        private String password;

                        @Transient
                        private String passwordIn;

                        private String phone;

                        @Column(name="RECORD_DATE")
                        private Timestamp recordDate;

                        private String salt;

                        private String status;

                        @Column(name="USER_STATUS")
                        private String userStatus;

                        public User() {
                        }
                // getters and setters
                }

Answer 7

You can use @JsonIgnoreProperties at class level and put variables you want to igonre in json in "value" parameter.Worked for me fine.

@JsonIgnoreProperties(value = { "myVariable1","myVariable2" })
public class MyClass {
      private int myVariable1;,
      private int myVariable2;
}

Answer 8

You can also do like:

@JsonIgnore
@JsonProperty(access = Access.WRITE_ONLY)
private String password;

It's worked for me

Answer 9

I was looking for something similar. I still wanted my property serialized but wanted to alter the value using a different getter. In the below example, I'm deserializing the real password but serializing to a masked password. Here's how to do it:

public class User() {

    private static final String PASSWORD_MASK = "*********";

    @JsonIgnore
    private String password;

    @JsonProperty(access = JsonProperty.Access.WRITE_ONLY)
    public String setPassword(String password) {
        if (!password.equals(PASSWORD_MASK) {
            this.password = password;
        }
    }

    public String getPassword() {
        return password;
    }

    @JsonProperty("password")
    public String getPasswordMasked() {
        return PASSWORD_MASK;
    }
}