Python replacement of Rubys grep?

Question

abc=123
dabc=123
  abc=456
  dabc=789
    aabd=123

From the above file I need to find lines beginning with abc= (whitespaces doesn't matter)

in ruby I would put this in an array and do

matches = input.grep(/^\s*abc=.*/).map(&:strip)

I'm a totally noob in Python, even said I'm a fresh Python developer is too much.

Maybe there is a better "Python way" of doing this without even grepping ?

The Python version I have available on the platform where I need to solve the problem is 2.6

There is no way of use Ruby at that time

Is this what you want? http://stackoverflow.com/questions/1921894/grep-and-python — Austin Salonen, Sep 16 '12 at 21:52

kindall · Accepted Answer · 2012-09-17T13:49:32.870

5

with open("myfile.txt") as myfile:
    matches = [line.rstrip() for line in myfile if line.lstrip().startswith("abc=")]

edited Sep 17 '12 at 13:49

answered Sep 16 '12 at 22:01

kindall

2

+1 startswith for clarity. I'd use `with open("myfile.txt") as myfile`. – dokkaebi Sep 17 '12 at 05:08
Thanks a lot! This is the outcome: https://github.com/astropanic/Compline As I said, I'm not a python pro, so please bear with me ;) – astropanic Sep 17 '12 at 20:58

user4815162342 · Answer 2 · 2012-09-16T22:05:25.490

1

In Python you would typically use a list comprehension whose if clause does what you'd accomplish with Ruby's grep:

import sys, re
matches = [line.strip() for line in sys.stdin
           if re.match(r'^\s*abc=.*', line)]

edited Sep 16 '12 at 22:05

answered Sep 16 '12 at 22:02

user4815162342

2 Answers2