Compare strings in java ignore special characters

Question

please could you help me with comparing two strings with special characters in the same way as MySQL does it? For example this two strings should be equal: "Dražík" and "Drazik"

You can probably get some ideas [here](http://stackoverflow.com/q/1453171/1343161). — Keppil, Aug 29 '12 at 06:49

score 3 · Accepted Answer · answered Aug 29 '12 at 06:46

3

Use a Collator . See Performing Locale-Independent Comparisons

answered Aug 29 '12 at 06:46

Pierre

33,089
29
109
185

And since I'm using this comparison in equals method, do you know how to make hashcode for such a string? I mean how to get the same hash for both Dražík and Drazik. – dpelisek Aug 29 '12 at 07:09
Is OK to use for that myCol.getCollationKey("Dražík").hashCode() ? – dpelisek Aug 29 '12 at 07:24

score 1 · Answer 2 · answered Aug 29 '12 at 06:51

1

Most probably getting the Edit Distance/ Levenshtein distance should resolve your issue. This is not an ideal solution but you may use it with significant success.

Check it Your Self

Levenshtein Distance in Java

answered Aug 29 '12 at 06:51

Chathuranga Chandrasekara

19,894
28
96
137

score -1 · Answer 3 · answered Aug 29 '12 at 06:49

-1

You can simply use the s.compareTo(z) function where s,z are the string names. It returns the difference between the first unmatched characters in the two strings

answered Aug 29 '12 at 06:49

Arghya Chakraborty

423
1
3
12

Compare strings in java ignore special characters

3 Answers3