Java get referer URI?

Question

I want the exact same method as getRequestURI(), but I want to use it on the referer. Is this possible?

I would like to turn http://www.example.com/my/path?vars=true into /my/path

are you looking for something in the servlet api or code that does what you want. — ams, Aug 16 '12 at 23:00
Please look at [this question](http://stackoverflow.com/questions/2648984/httpservletrequest-how-to-obtain-the-referring-url) and its answer, it'll tell you how to get the request URI as well as the pitfalls of trusting it. — Amos M. Carpenter, Aug 16 '12 at 23:00
Ah, didn't see your edit when I posted my comment. Your phrase "use it on the referer" is still a bit misleading. Jon's answer should do it for you then. — Amos M. Carpenter, Aug 17 '12 at 04:19

score 12 · Accepted Answer · answered Aug 17 '12 at 03:58

12

You want something like this?

String refererURI = new URI(request.getHeader("referer")).getPath();

answered Aug 17 '12 at 03:58

Jon Lin

That looks like something that would work :). I'll give it a try right now. – mowwwalker Aug 17 '12 at 04:17
Yup, that worked! I remember coming across this when looking things up, but it hadn't worked for whatever reason. I'll have to figure it out when I get back into work. – mowwwalker Aug 17 '12 at 04:35
Are there constants in the servlet API defining common header names? – rudolfson Apr 14 '15 at 08:24

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