Path to a file without basename

Question

How can I get the path of a file without the file basename?

Something like /a/path/to/my/file.txt --> /a/path/to/my/

Tried with .split() without success.

score 151 · Accepted Answer · answered Aug 01 '12 at 10:44

151

Use os.path.dirname(filename).

answered Aug 01 '12 at 10:44

Daniel Roseman

score 10 · Answer 2 · answered Aug 01 '12 at 10:45

10

You can import os

>>> filepath
'/a/path/to/my/file.txt'
>>> os.path.dirname(filepath)
'/a/path/to/my'
>>>

answered Aug 01 '12 at 10:45

aayoubi

score 5 · Answer 3 · answered Aug 01 '12 at 10:49

5

(dirname, filename) = os.path.split(path)

answered Aug 01 '12 at 10:49

Igor Chubin

more precisely: `(rest, first_path_item) = os.path.split(path)` – estani Nov 16 '12 at 15:14

score 4 · Answer 4 · edited Aug 02 '12 at 12:24

4

Check subs of os.path

os.path.dirname('/test/one')

edited Aug 02 '12 at 12:24

sloth

answered Aug 01 '12 at 10:45

tuxuday

score 2 · Answer 5 · answered Dec 06 '21 at 12:49

2

Since Python 3.4 you can use Pathlib.

from pathlib import Path

path = Path("/a/path/to/my/file.txt")
print(path.parent)

answered Dec 06 '21 at 12:49

Arigion

5 Answers5