Bug in Javascript parseInt method?

Question

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Workarounds for JavaScript parseInt octal bug

Parsing a string using parseInt method returns invalid output .

Code :

parseInt("08");

Excepted Output :

Real Output :

Code [This returns output correctly] :

parseInt("8")

Output :

Why it happens ?

Simple googling would also have solved this: http://www.w3schools.com/jsref/jsref_parseint.asp — Michael, Jun 26 '12 at 08:01
Googling your exact question title also brings up the answer... — thirtydot, Jun 26 '12 at 09:45

score 3 · Accepted Answer · edited Jun 26 '12 at 08:07

3

You need to specify the base:

parseInt("08",10); //=>8

Otherwise JavaScript doesn't know if you are in decimal, hexadecimal or binary. (This is a best practise you should always use if you use parseInt.)

edited Jun 26 '12 at 08:07

JJJ

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answered Jun 26 '12 at 07:59

beardhatcode

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score 2 · Answer 2 · edited May 23 '17 at 10:34

2

Also see Number:

Number("08"); // => 8

edited May 23 '17 at 10:34

Community

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answered Jun 26 '12 at 08:01

Gareth

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score 1 · Answer 3 · answered Jun 26 '12 at 07:59

You should tell parseInt its 10 based:

parseInt("08", 10);

JavaScript parseInt() Function

If the radix parameter is omitted, JavaScript assumes the following:

If the string begins with "0x", the radix is 16 (hexadecimal)

If the string begins with "0", the radix is 8 (octal). This feature is deprecated If the string begins with any other value, the radix is 10 (decimal)

http://jsfiddle.net/YChK5/

score 0 · Answer 4 · answered Jun 26 '12 at 08:01

Strings with a leading zero are often interpreted as octal values. Since octal means, that only numbers from 0-7 have a meaning, "08" is converted to "0". Specify the base to fix this problem:

parseInt("08", 10); // base 10

As usual, the MDN is a good source of information: https://developer.mozilla.org/en/JavaScript/Reference/Global_Objects/parseInt#Octal_Interpretations_with_No_Radix

Bug in Javascript parseInt method?

4 Answers4