Django Build URLs from template with integer param, the primary key

Question

I have this link in a template:

<a href="{% url show_item item.id %}">Item 1</a>

and this url in the urls.py

url(r'item/(?P<id>)/$', show_item, name="page_item")

however, this error occurs:

Reverse for 'show_item' with arguments '(63L,)' and keyword arguments '{}' not found.

I looked at this question:

but it did not help.

Is there another way to use the primary key, which is an integer, in constructing URLs in templates?

score 15 · Accepted Answer · answered Jun 22 '12 at 01:54

15

The URL name doesn't match. Change the template to be:

<a href="{% url page_item item.id %}">Item 1</a>

answered Jun 22 '12 at 01:54

Ned Batchelder

accepting this as an answer, although also take note that there should be a \d on the captured param – yretuta Jun 25 '12 at 01:49
1

As of Django 1.8, there should be quotes around url name: `Item 1 – Vincent van Leeuwen Jul 31 '15 at 13:00

score 1 · Answer 2 · answered Jun 22 '12 at 01:55

1

It should be page_item not show_item in template.

answered Jun 22 '12 at 01:55

iMom0

2 Answers2