python regular expression date format mm/dd

Question

I'm trying to write an RE to find all mm/dd format

re = "((1[0-2])|(0?[0-9]))/(((1[0-9])|(2[0-9])|(3[0-1])|(0?[0-9])))"

It finds all mm/dd format but also gives things like,

11/22 in 12311/22213

and

10/22 in 1110/22213

How do I exclude the cases above?

Thanks

score 1 · Accepted Answer · edited May 23 '17 at 12:20

1

(?<!\d)((1[0-2])|(0?[0-9]))/(((1[0-9])|(2[0-9])|(3[0-1])|(0?[0-9])))(?!\d)

Of course it'll match stuff like 02/31, but that's a start. I posted here a regex that matches only valid dates.

edited May 23 '17 at 12:20

Community

answered Jun 01 '12 at 03:34

dda

The very edge case is 02/29, which is valid in some years, and not in others. – nhahtdh Jun 01 '12 at 03:46
2

That one is impossible to catch by regex :-) – dda Jun 01 '12 at 04:29

1 Answers1