How to generate a 'enter' event?

Question

it is possible to generate a click event like this.

$("#elementId").trigger("click");

but I am confused how we can generate an 'enter' event similarly? I searched through internet and one way I found was,

$("#elementId").trigger("keypress",[13]);

but this is not working for me? Is this is correct? or is there any other way to do this?

what do you mean by "enter"? the enter key is pressed, or mouse entering the area? — jimpic, May 15 '12 at 08:10
http://stackoverflow.com/questions/832059/definitive-way-to-trigger-keypress-events-with-jquery — Andreas Wong, May 15 '12 at 08:15
i don't think its programatically possible to fire user-driven event like click itself, if so i could trigger the event to open ads on my site when a user visits a page similar to invoking [clickjacking](http://en.wikipedia.org/wiki/Clickjacking) and pose a security risk — optimusprime619, May 15 '12 at 08:16
@jimpic, certainly it was enter key press, not mouse entering area. — Jinesh, May 15 '12 at 08:27

score 1 · Accepted Answer · answered May 15 '12 at 08:12

1

Do you mean something like:

var e = jQuery.Event("keydown");
e.which = 13; // # Some key code value for Enter
$("input").trigger(e);

answered May 15 '12 at 08:12

Sudhir Bastakoti

Andreas Wong · Answer 2 · 2012-05-15T08:21:20.840

1

This?

var e = $.Event("keydown", { keyCode: 13 });
$("#elementId").trigger(e);

edited May 15 '12 at 08:21

answered May 15 '12 at 08:12

Andreas Wong

score 1 · Answer 3 · answered May 15 '12 at 08:12

1

You can use the following code to trigger a Enter keypress event

var e = jQuery.Event("keydown");
e.which = 13; // # Enter key code value
$("#elementId").trigger(e);

answered May 15 '12 at 08:12

score 0 · Answer 4 · answered May 15 '12 at 08:10

your syntax is incorrect. if you need the keycode try:

$("#elementId").keypress(function(e) {
  if ( e.which == 13 ) {
     //do stuff here
   }    
});

if you just want an event once the element is focus, try the focus() syntax.

$("#elementId").focus(function(){ ... });

4 Answers4