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Possible Duplicate:
In the bash shell, what is “ 2>&1 ”? 

#echo "[+] Creating $count files" 
_remount 
create=$((time ./dirtest $testdir $count $size) 2>&1)
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Anders Lind
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    From [this question](http://stackoverflow.com/questions/818255/in-the-bash-shell-what-is-21), it's a redirect of stderr to stdout. – simont Apr 14 '12 at 17:29

2 Answers2

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It means that the standard error descriptor stderr (2) is to be redirected to the standard output descriptor stdout (1). Notice that the & ensures that the 1 is interpreted as a file descriptor and not a filename.

Óscar López
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It redirects standard error to the standard output. This way the result written to stderr will be stored in the variable.

Karoly Horvath
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