hasattr with functions

Question

How to check attr existence in function or method with hasattr (or without)? When I try to check it is False in any way:

>>> def f():
        at = True


>>> hasattr(f, 'at')
False
>>> hasattr(f(), 'at')
False

What do you hope to do with the information? – Karl Knechtel Apr 13 '12 at 06:45 — Karl Knechtel, Apr 13 '12 at 06:45

score 5 · Accepted Answer · answered Apr 13 '12 at 05:21

5

Local variables are not attributes. You cannot use any *attr() to frob them.

answered Apr 13 '12 at 05:21

+1. @I159: if you *really* want to see what local variables a function is using, [this code](http://stackoverflow.com/questions/1360721/how-to-get-set-local-variables-of-a-function-from-outside-in-python) is out there, but what on earth would be your use case? – David Robinson Apr 13 '12 at 05:25

score 0 · Answer 2 · answered May 02 '16 at 19:02

0

It should work, look at below example.

>>> def f():
...    f.at = True
...
>>> hasattr(f, 'at')
False
>>> f()
>>> hasattr(f, 'at')
True

answered May 02 '16 at 19:02

Jianping Shen

2 Answers2