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Is there any function in Apex which could emulate functionality of the CASESAFEID() formula function? I'm trying to get 18-char Id variant from the standard one.

dino ursic
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2 Answers2

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Per the Apex docs on primitive datatypes, "Note that if you set [an] ID to a 15-character value, Apex automatically converts the value to its 18-character representation." So it should be enough to assign your 15 character id to an ID-typed variable, and then back to a string, like so:

string idStr = '001E000000nwg7g';   // 15 character id
id idval = idStr;                   // assign to ID variable
idStr = idval;                      // back to string to prove the point
system.debug('18 char: ' + idStr);  // note that you could just append idval instead
                                    // of converting to string first

Remember that assigning an invalid id string to an ID-typed variable will throw an exception; if there's any chance that your 15 character value may not be a valid id, wrap the assignment in a try/catch block.

Jason Clark
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  • Good enough for me :) Thank you, Jason! – dino ursic Jan 30 '14 at 14:06
  • Thanks for breaking this down line by line for understanding. Assuming you start with accountId as a 15 char string, one could get this done in one line: accountId = (String)(Id)accountId. – Swisher Sweet Dec 30 '19 at 17:28
  • @SwisherSweet in fact, you can just use accountId = (Id)accountId;, as Id values are always implicitly cast to 18-character strings whenever they are used as strings. – Jason Clark Dec 30 '19 at 18:33
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You can just type the string cast to ID. Like (Id) idStr;

zuke
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