I assume you are talking about a Bode plot of a transfer function response, which relates the input of a system to the output in the frequency domain. One way of measuring such a response would be to input a sinusoidal signal of one particular frequency, and measure the amplitude and phase shift of the output. So the input will have the following form,
$$
x_{in}(t) = A \sin(\omega t).
$$
The output will always also be a sinusoidal signal of the same frequency, assuming that the dynamics of the system are linear, so no $\dot{x}=x^2$, but possibly with a different amplitude and phase. So the output will have the following form,
$$
x_{out}(t) = B \sin(\omega t + \phi).
$$
The amplitude would actually be the ratio of $B/A$ and $\phi$ would be the phase shift.
There are more efficient ways of measuring a transfer function, however I think this helps explain the meaning of the Bode plot of a transfer function in the frequency domain.
Usually a logarithmic scale is used for the frequency axis of a Bode plot, just as the amplitude (usually with decibel). A linear scale usually used for the phase information. A transfer function usually expressed in complex values instead of amplitude and phase, since that information can also be extracted from complex numbers. When you want to find the response of a system, you can just multiply the transfer function by the frequency domain of the input signal (when you have amplitude and phase separate, you can multiply the amplitudes and add the phases).
The frequency domain of a step function has a constant nonzero amplitude and constant phase for all frequencies. If you would multiply this by the transfer function you would basically get the transfer function back (possibly scaled) as the frequency domain of the output signal. Since all sinusoidal signals oscillate around zero, therefore you can find the offset from zero (I assume you mean this by statical error) by looking at the amplitude of the output at 0 Hz.