My question is from Nicholson-Snyder's text , E-book here.
My question is here, from page 217 of the book. (I can't post image as my reputation is not enough.)
How did we get $W_g=W_b$ from $\dfrac{U'(W_g)}{U'(W_b)}=1$ ?
My question is from Nicholson-Snyder's text , E-book here.
My question is here, from page 217 of the book. (I can't post image as my reputation is not enough.)
How did we get $W_g=W_b$ from $\dfrac{U'(W_g)}{U'(W_b)}=1$ ?
$U$ is usually strictly concave. So $U'$ is strictly decreasing and is therefore injective.