You have created a computer, but it is not working, only printing sets of 4 characters in a sequence. If you can predict the next 3 sets, then you can restart the computer and set it up so you can actually use it. The computer will print out 1 more set every day at a random time.
Sequence:
3826
³¸²¶
sxrv
óøòö
no_output
no_output
KDJN
no_output
Ok, got a new answer..
It appears that ...
the first number in each set is just the computer counting by 1s, but you've mixed up the least significant bit with the most significant bit..
That is the first number in each set is ...
'3' --> decimal 51 --> binary 00110011
'³' --> decimal 179 --> binary 10110011
's' --> decimal 115 --> binary 01110011
etc..
So the next three sets (after the final no_output that was added to the question later) will start with ...
binary 00101011 --> decimal 43 --> '+'
binary 10101011 --> decimal 171 --> '«'
binary 01101011 --> decimal 107 --> 'k'
Therefore the next three patterns are:
+$*.
«¤ª®
kdjn
Hope I did those conversions right.. I feel better about this answer than my previous one.
I think the next three are:
ËÄÊÎ
no_output
ċĄĊĎ
because
the characters are based on the Unicode table, where each set of 4 is val, val+5, val-1, val+3 and patterns fluctuate between adding 128 then subtracting 64.
so
Using the decimal values for the codes the first 4 patterns are:
51 56 50 54 (51, 51+5, 51-1, 51+3)
179 184 178 182 (51+128, 51+128+5, 51+128-1, 51+128+3)
115 120 114 118 (179-64, 179-64+5, 179-64-1, 179-64+3)
243 248 242 246 (115+128, 115+128+5, 115+128-1, 115+128+3)
and the pattern continues..